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rrpaul
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Joined: 14 Jan 2010
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 Posted: Mon Feb 08, 2010 11:57 pm Post subject: |
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| SalsaShark wrote: | | You're going to college to learn, are you not? |
Shit, not math lol.
And how do I learn from my mistakes if I don't even know what I did wrong????
Lol, no I know, I'm just lazy
me so sowwy 
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sasuke
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Joined: 19 Jul 2009
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| Posted: Tue Feb 09, 2010 12:10 am Post subject: |
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rrpaul: For problem 8, I can't remember anything about Taylor series, or any series anymore, but you can get around it:
On one hand, you have that the sum of (x to the 3n) with n going from 1 to infinity = 28/8 = 3.5.
On the other hand, if you play with that sum a little, you will find that if you factor an x cubed out of it, you will then have:
x cubed * (1+ x cubed + x to the 6 + ...) which in turn is equal to x cubed * (1 + the original sum itself), which is also equal to 3.5. You now have a single equation with one variable which should be easy to solve, namely: x cubed * (1 + 3.5) = 3.5. So x is the cube root of 7/9.
I was going to ask Salsa to double check the above, but it looks like he thinks that you should learn this stuff. |
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SalsaShark
Cheesecake Dick
Joined: 07 Aug 2006
Posts: 6286
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Location: Waterloo ON
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| Posted: Tue Feb 09, 2010 12:21 am Post subject: |
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Ahhh shit, it's a sum from n=1 not from n=0... what kind of stupid shit is that? I did my work wrong.
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SalsaShark
Cheesecake Dick
Joined: 07 Aug 2006
Posts: 6286
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Location: Waterloo ON
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| Posted: Tue Feb 09, 2010 12:32 am Post subject: |
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See, the plus side of not telling you the answer to the question is that I would have told you the wrong answer. My method still works, but it sasuke's method works just as well.
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rrpaul
Forum Leader
Joined: 14 Jan 2010
Posts: 581
Local time: 8:24 AM
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| Posted: Tue Feb 09, 2010 12:35 am Post subject: |
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| sasuke wrote: | rrpaul: For problem 8, I can't remember anything about Taylor series, or any series anymore, but you can get around it:
On one hand, you have that the sum of (x to the 3n) with n going from 1 to infinity = 28/8 = 3.5.
On the other hand, if you play with that sum a little, you will find that if you factor an x cubed out of it, you will then have:
x cubed * (1+ x cubed + x to the 6 + ...) which in turn is equal to x cubed * (1 + the original sum itself), which is also equal to 3.5. You now have a single equation with one variable which should be easy to solve, namely: x cubed * (1 + 3.5) = 3.5. So x is the cube root of 7/9.
I was going to ask Salsa to double check the above, but it looks like he thinks that you should learn this stuff. |
Oh, I get it now, I feel stupid, I didn't think of factoring.
Thnx....and I did actually learn something lol
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"Science flies you to the moon. Religion flies you into buildings."
- Victor Stenger
"Livin' Life As It Is."
- Paul |
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